The speed of a projectile when it reaches its maximum height is 0.58 times its speed when it is at half its maximum height. what is the initial projection angle of the projectile?

The initial projection angle of the projectile is arc tangent of the ratio of vertical velocity component to the horizontal. Angle is 70.4 degrees.

Projectile motion is the motion of the body, when it is thrown in the air taking the action of gravity on it.

It is given that the maximum height reached by the projectile is 0.58 times its speed when it is at half of its maximum height.

Suppose the is the speed of the projectile at the maximum height and is the speed of the projectile at the half of its maximum height

As maximum height reached by the projectile is 0.58 times its speed when it is at half of its maximum height. Therefore,

Now at the maximum speed the vertical component of velocity is zero. Thus,

Squaring both sides, we get,

From the third equation of motion at the distance of half of the maximum height,

Let the above equation as equation 1.

The height of the projectile can be given as,

Put this value in the equation one, we get,

Comparing both the values of , we get,

For the angle of projection, we know that,

Thus, the initial projection angle of the projectile is 70.4 degrees.

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Speed of the projectile at its maximum height is only along horizontal direction

so at highest point

now when he is at half of the maximum height the speed will be in x and y direction both

here it is given that

also we know that

here we know that maximum height is given as

now from above

also we know that angle of projection is

so angle is

statement #3 on andre"s list is false.