Acannon is mounted on a tower above a wide, level field. the barrel of the cannon is 20 m above the ground below. a cannonball is fired horizontally with an initial speed of 700 m/s. assuming air resistance can be neglected, approximately how long will the cannonball be in flight before it hits the ground?

  Cannonball will be in flight before it hits the ground for 2.02 seconds

Explanation:

  Initial height from ground = 20 meter.

  We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 , we need to calculate time when s = 20 meter.

  Substituting

  So it will take 2.02 seconds to reach ground.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

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