Ahelicopter is ascending vertically with a speed of 5.10m/s. at a height of 105m above the earth, a package is dropped from a window. how much time does it take for the package to reach the ground? (hint: the package initial velocity equals the helicopter velocity)

The time required by the package to reach the ground will be 5.12 seconds.

Given:

The helicopter  is ascending vertically with a speed of .

Now, the package is dropped from the height of . Height is negative because it is decreasing.

Initial velocity of the package is .

The acceleration acting on the package will be, . acceleration is negative because it is acting downwards.

Use the second equation of motion to find the time required to reach the ground.

Solve the above quadratic equation to find the value of time as,

Therefore, the time required by the package to reach the ground will be 5.12 seconds.

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Here it is given that initial speed of the package will be same as speed of the helicopter

displacement of the package as it is dropped on ground

acceleration is due to gravity

now by kinematics

by solving above equation we have

so it will take 5.2 s to reach the ground

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west