Askier is gliding along at 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10" incline. his speed at the bottom is 15 m/s. a. what is the length of the incline? b. how long does it take him to reach the bottom?

The length of the inclined plane is 63.53 m and the time taken by the skier to cover the distance is 7.0588 sec.

Given to us

Velocity, u = 3.0 m/s

Angle of Inclination = 10"

Velocity of skier at the bottom, v = 15 m/s

We know that acceleration of the skier on the inclined plane can be given as,

a = g sin(θ)

a = g sin(10)

a= 9.81 x 0.1736

a = 1.70 m/sec²

We know that according to the third equation of motion

Substitute the values,

Using the first equation of motion,

Hence, the length of the inclined plane is 63.53 m and the time taken by the skier to cover the distance is 7.0588 sec.

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acceleration of the skier on the inclined plane is given by

now by equation of kinematics

so the length of inclined plane will be 63.53 m

Part b)

Time to reach the bottom will be given by

so it will take 7.06 s to reach the bottom

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2