The “reaction time” of the average automobile driver is about 0.7 s. (the reaction time is the interval between the perception of a signal to stop and the application of the brakes.) if an automobile can slow down with an acceleration of 12 ft/s^2 compute the total distance (in feet) covered in coming to a stop after a signal is observed from an initial velocity of 55 mi/h. let 1 mi/h = 1.466 ft/s.

KINEMATICS

Uniform or constant motion in a straight line (rectilinear). Speed or velocity constant and/or acceleration constant. If motion is up and down and/or has an up and down component then acceleration omn earth will be g. g is about 10m/s/s.

speed = distance/time

velocity = displacement/time

s=distance ... u=initial speed ... v = final speed ... a = acceleration ... t = time

v=u+at

v^2=u^2+2as

s=ut+1/2at^2

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

your answer is c! hope this : )