What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of −25.0 nc? g?

To calculate the force between two negative charges, we use the formula which is given by the Coulomb`s Law as

Here, and are the charges on the pith balls, r is the separation between the charges and k is constant and its value is  .

Given   and  .

Substituting these values in above formula we get,

Thus, the repulsive force between two pith balls is .

Solution:

The force between two charges given by Columb's law i

Solution:

The force between two charges given by Columb's law i

the rearrangement of particles in a physical change. hope this

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