Four 21.2 ω resistors are connected in parallel across a 35.8 v ideal battery. what is the current through the battery?

The resistors behavelike a single resistor of (21.2/4) = 5.3 ohms.

The total current through the parallel bunch of resistors is E/R = 35.8/5.3 = 6.75 Amperes.

That's the total current SUPPLIED by the battery. Current doesn't flow 'through' a battery.

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j