Can the magnitude of the displacement vector be more than the distance traveled less than the distant traveled explain

The displacement of a body will always be less than or equal to the distance traveled. It cannot have a value greater than the distance traveled.

Distance is the length of the path traveled by the body, while displacement is the shortest distance between the starting and the ending point.

Consider a body moving from point A to B along the curved path as shown in the diagram. The distance traveled is the length of the curved path from A to B.

The displacement of the body is measured along the straight line drawn from A to B.

It can be seen that the distance traveled is greater than the displacement. The distance traveled will be equal to the displacement if the body travels along the straight line drawn from A to B.

Since the displacement is always the shortest distance between the starting and ending point, it can have a value less than or equal to the distance traveled.

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)

Maybe because they hurt or you bleed a lot