Acar drives at a constant speed of 14 m/s around a circle with radius 55 m. what is the centripetal acceleration of the car? a. 2.3 m/s2 b. 3.6 m/s2 c. 3.9 m/s2 d. 0.25 m/s2

Option (B) is correct. a= 3.6 m/s²

Explanation:

The centripetal acceleration is given by

a= v²/r

v= velocity=14 m/s

r= radius=55 m

a= (14)²/(55)

a=3.6 m/s²

Answer : The correct option is, (B)

Explanation :

The formula used for centripetal acceleration is:

where,

= centripetal acceleration = ?

v = velocity of car = 14 m/s

r = radius = 55 m

Now put all the given values in the above formula, we get:

Therefore, the centripetal acceleration of the car is

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

frequency or wavelenth of em radiation in a vacuum