Phosphorus 32 has a half life of 14.3 days how much of a 4mg sample of phosphorus - 32 will remain after 71.5 days

Let us first find out the radioactive constant of Phosphorus 32.

Radioactive constant, λ =

Here, is half life of phosphorus 32 = 14.3 days

λ =

The amount of 4 mg of phosphorus remain after 71.5 days can be found using the formula,

m=m₀e⁻(λt)

=

=

=

=

=

= 0.125 mg

The mass of 4 mg of phosphorus 32 remains after 71.5 days will be 0.125 mg.