Calculate the moment of inertia of a bicycle wheel 66.7 cm in diameter. the rim and tire have a combined mass of 1.25 kg. the mass of the hub can be ignored since it distance from the axis of rotation is so small.

Moment of inertia of the wheel= 0.139 kg m²

Explanation;

diameter of wheel=66.7 cm=0.667 m

radius=d/2 =0.667/2=0.3335 m

The moment of inertia of a wheel is given by

i= m r²

m= mass of the wheel=1.25 kg

r= radius of wheel=0.3335 m

i= 1.25 (0.3335)²

i=0.139 kg m²

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm