Acapacitor stores 7.6 × 10–11 c when the electric potential difference between the plates is 5.8 v. what is the electric potential energy stored in the capacitor?

Energy stored in the capacitor= 2.2 x 10⁻¹⁰ J

Explanation:

The energy stored in the capacitor is given by

E= 1/2 q V

E= energy stored

q= charge= 7.6 x 10⁻¹¹ C

V= potential difference=5.8 V

so energy stored= E= 1/2 (7.6 x 10⁻¹¹) (5.8)

Energy stored= 2.2 x 10⁻¹⁰ J

this is a good question! i'll do some research and come back when i have the answer!

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