Asky diver jumps out of an airplane at a height of 5010 ft. if her parachute does not open until she reaches 1010 ft, what is her velocity (in ft/s) at that point if air resistance is neglected?

Given:

Height from which diver jumps h(i)=5010 ft

Height from which diver open the parachute h(f)=5010 ft

calculate the net height h= h(i)-h(f)

substitute the values in the above equation

h= 5010-1010= 4000 ft

calculate the velocity of the diver at the net height.

here g is acceleration due to gravity = 32.2 ft per second square

h is the net height

substitute the values in the above equation

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

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