Ahot–air balloon is moving at a speed of 10.0 meters/second in the +x–direction. the balloonist throws a brass ball in the +x–direction at a velocity of +4 meters/second with respect to himself. if the ball lands after 30 seconds, about how far does it land horizontally from the point at which it was released? a. 120 meters b. 125 meters c. 300 meters d. 420 meters

Option (D) is correct.

The balloon lands horizontally at a distance of 420 m from a point where it as released.

Explanation:

Velocity of air balloon along +X axis =10 m/s

velocity of ball=4 m/s along + X axis

the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s

time taken= 30 s

The distance traveled is given by d= v t

d= 14 (30)

d= 420 m

Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//