Acar slows to a stop in 5 seconds. if it was going 80 km/hr find the acceleration.

Given

time (t) = 5 seconds

Initial speed (u) = 80 km/hr = 22.2222m/s

final speed (v) = 0 km/hr =0m/s

Note I change to m/s so as to be consistent with units

formula: V=U+at where a is acceleration

0=22.2222+5a

a=22.2222/5

acceleration = 4.44444 m/s^2

answer: i don't know the answer good luck

explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂