An engine performs 6400 j of work on a motorbike the motorbike and the rider have a combined mass of 200 kg if the bike started at rest what is the speed of the bike after the work is performed

The speed of the bike after the work is performed is 8 m/s

Energy, mass and velocity of an object is related according to the following equation:

Energy (E) = ½ × mass (m) × Square velocity (v²)

E = ½mv²

With the above formula, we can obtain the velocity of the bike as follow:

E = ½mv²

6400 = ½ × 200 × v²

6400 = 100 × v²

Divide both side by 100

v² = 6400 / 100

v² = 64

Take the square root of both side

v = √64

v = 8 m/s

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The work done by the engine is converted into kinetic energy of the motorbike+rider system:

where

W=6400 J is the work

m=200 kg is the mass of the system

v is the speed acquired by the motorbike

Rearranging the equation and substituting the numbers in, we find

50 inches should be the resultant vector