Physics, 15.07.2019 15:30 crodriguez87

You accelerate your car from rest at a constant rate down a straight road, and reach 22.0 m/s in 117 s. the tires on your car have radius 0.320 m. assuming the tires rotate in a counterclockwise direction, what is the angular acceleration of the tires?

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Answer from: econsta3

For this case, the first thing to do is find the linear acceleration of the car.

We have then:

$a = \frac{v}{t}$

Where,

v: speed

t: time

Substituting values we have:

$a = \frac{22}{117}$

$a = 0.19 \frac{m}{s^2}$

We are now looking for angular acceleration.

For this, we use the following equation:

$\alpha =\frac{a}{r}$

Where,

a: linear acceleration

r: radius of the tires

Substituting values we have:

$\alpha = \frac{0.19}{0.320}$

$\alpha = 0.59 \frac{rad}{s^2}$

The angular acceleration of the tires is:

$\alpha = 0.59 \frac{rad}{s^2}$

Answer from: Quest

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Answer from: Quest

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You accelerate your car from rest at a constant rate down a straight road, and reach 22.0 m/s in 117...