Through what potential difference δv must electrons be accelerated (from rest) so that they will have the same wavelength as an x-ray of wavelength 0.185 nm ?

The De Broglie wavelength of the electron is equal to

where h is the Planck constant and p is the electron's momentum. Since this wavelength must be equal to that of the x-ray,

we can re-arrange the previous equation to find the momentum of the electron:

The kinetic energy of the electron is equal to the square of the momentum divided by twice its mass:

When the electron is accelerated by a potential difference , the energy it gains is

where q is the electron charge. Re-arranging the formula, we find the potential difference:

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg