At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. what is the volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa?

V = 1.66 L

Explanation:

As we know that at the depth of 10 m the volume of the lungs of diver is given as

V = 2.40 L

Temperature = 32 degree C

Pressure = 101.30 kPa

Now we have change the values of pressure and temperature

Pressure = 141.20 kPa

Temperature = 21 degree C

Now we can use idea gas equation to solve this

so we have

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.