As part of an exercise program, a woman walks south at a speed of 2.00 m/s for 60.0 minutes. she then turns around and walks north a distance 3000 m in 25.0 minutes (a) what is the woman's average velocity during her entire motion? a.0.824 m/s south b.1.93 m/s south c.2.00 m/s south d.1.79 m/s south e.800 m/s south

The woman's average velocity can be calculated by dividing the total distance covered during the motion by the total time of the motion.

In the first part of the motion, the woman moved south with speed v1=2.00 m/s for a time of

therefore the distance she covered is


In the second part of the motion, she moved north for  in a time of


Since she moved in the opposite direction, the total distance covered is the difference between S1 and S2:
(south)

While the total time of the motion is


Therefore, the woman's average velocity is
(south)

and the correct answer is A).