Which function's graph has asymptotes located at the values x=pi/2+-npi? 1. y = sin x2. y = sec x3. y = cot x4. y = tan x  a) 2 onlyb) 1 onlyc) 1 and 3 onlyd) 2 and 4 only

Option 2 and 4

Step-by-step explanation:

Given : Function's graph has asymptotes located at the values

To find : Which function graph has asymptote given?

Solution :

An asymptote is a line or curve that approaches a given curve.

To find vertical asymptote the limit has to go to either  ∞  or  − ∞  , which happens when the denominator becomes zero.

The sine are defined for all real x, y is defined for all real x, so there are no vertical asymptotes.

So, Option 1 is not true.

In option 3,

When we put Denominator = 0

Value of x lie between

So, Option 3 is not true.

In Option 2,

When we put Denominator = 0

When cos x=0 the values of x is

Therefore, The graph of y= sec x has asymptote located at the values

So, Option 2 is correct.

In Option 4,

When we put Denominator = 0

When cos x=0 the values of x is

Therefore, The graph of y= tan x has asymptote located at the values

So, Option 4 is correct.

Therefore, Option 2 and 4 are correct.

Hence Option A is correct - 2 only

it is x=-4

step-by-step explanation: