Mathematics, 21.07.2019 08:00 kalo1023

Factor the following problems show your work 1. x^2+16x+24 2. x^2-10a+25

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Answer from: jwhit28

x^2+16x+24: Think: What are the integer factors of 24? I'd list 1, 2, 3, 4, 6, 8, 12 and 24. Next: Look for a pair of factors from that list that:

(1)ADD up to 16 AND (2) whose product is 24. Unfortunately there seems to be no such pair from the above list.

So: Use the quadratic formula to find the roots of x^2+16x+24:

-16 plus or minus sqrt[ 256-4(1)(24) ]
x =
2
-16 plus or minus sqrt(160) -16 plus or minus 4 sqrt(10)
= =
2 2
2(-8 plus or minus 2 sqrt(10) )
= = -8 plus or minus 2sqrt(10)
2

If c is a root, (x-c) is a factor. Thus, if -8 plus 2sqrt(10) is a root,

(x+8-2sqrt(10) is a factor. Can you find the other factor?

x^2-10a+25 is much easier to factor. The sqrt of 25 is 5, so try x= -5 as a root. Dividing x-5 into x^2-10a+25, we get x-5. Therefore, the factors are

(x-5) and (x-5).

Answer from: Quest

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

=3x+1

=3(2)+1

since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

=x+1

=2+1

now, let's find g(2)g(2):

g(x)

g(2)

=2x

=2⋅2

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

Answer from: Quest

more detail

step-by-step explanation:

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Factor the following problems show your work 1. x^2+16x+24 2. x^2-10a+25...