What is the vertex of the graph y = x^2 + 6x - 4?

The vertex of this equation is (-3, -13)

You can find any vertex by first looking for the x value. You can find the x value by using the following equation.

-b/2a

In this equation, 'a' refers to the coefficient of x^2 (1) and 'b' refers to the coefficient of x (6). So we can use these numbers to find the x value.

-b/2a

-(6)/2(1)

-6/2

-3

Now that we have the x value, we can substitute the value in for x and solve for the y value.

x^2 + 6x - 4

(-3)^2 + 6(-3) - 4

9 - 18 - 4

-13

And this gives you the ordered pair of (-3, -13)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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