On february 1, the electricity meter reading for the smith residence was 19,423 kilowatt hours. on march 1, the meter read 20,288 kilowatt hours. on april 1, the meter read 21,163 kilowatt hours. a. how many kilowatt hours of electricity did the smiths use during february? b. how many kilowatt hours did they use during march?

A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
The Smiths used 875 kilowatt hours of electricity during March

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.