The first 50 miles of the drive is easy, while the last 68 miles of the drive is filled with curves. they drive at an average of 9 miles per hour faster for the first 50 miles of the trip. the entire trip takes 3 hours. how fast did they drive for the first 50 miles of the trip?

d = rt  

t = d/r  

3 = 50/(x+9) + 68/x  

x = 36mph  

36mph + 9mph = 45mph  

They traveled at 45mph for the first 50 miles and 36mph for the last 68 miles.

this is answer of 144 cubic meters

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;