Which functions represent the arithmetic sequence 8, 1.5, –5, –11.5 . . ? check all that apply. f(n) = –6.5n + 14.5 f(n) = –1.5n + 9.5 f(n) = 6.5n + 1.5 f(1) = 8, f(n + 1) = f(n) – 6.5 f(1) = 8, f(n + 1) = f(n) – 1.5 f(1) = 8, f(n + 1) = f(n) + 6.5

f(n) = –6.5n + 14.5

f(1) = 8, f(n + 1) = f(n) – 6.5

Step-by-step explanation:

The nth term of an arithmetic sequence is given as

Tn = a + (n-1)d

where a is the first term and d is the common difference between two consecutive terms

From the given sequence,

a = 8, d = 1.5 - 8

d = -6.5

As such, Tn = f(n) = 8 + (n-1)-6.5

= 8 - 6.5n + 6.5

= 14.5 - 6.5n

f(1) = 8

f(n + 1) - f(n) = – 6.5

f(n + 1) = f(n) – 6.5

answer: $1794

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube