Mathematics, 21.07.2019 16:00 ShawnSaviro4918
Iam first going to try finding the tangent line at this point: take the derivative: dy/dx = (3x^2 - e^x)/2y solve using (0, 1) dy/dx = (0 - 1)/6 = -1/6 i believe that -1/6 is the slope of the tangent line, so the slope of the normal line should be +6, right?
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Iam first going to try finding the tangent line at this point: take the derivative: dy/dx = (3x^2...
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