A3-lb force acting in the direction of the vector (3,-1) moves an object just over 9 ft from point (0,5) to (6,-2). find the work done to move the object to the nearest foot-pound

The Work done to move the object is  

Step-by-step explanation:

Given;

Force F=3

Vectors of F= (3,-1)

Moves object to a distance=9

Let A and B be the displacements Vectors

A= (0,-5)

B= (6,-2)

To Find:

Work done in foot-pounds

Solution:

Work done

Direction of force vector= (3,-1)  (i, j)  

                                        =3i-j

Unit of force vector

Force vector=(Force/Unit Vector)Direction of  force vectors

                   F=

Direction of motion vector= (B-A)  

                                          = (6,-2)-(0,-5) x i,j)

                                          =(6-0),(-2-5) x (i, j)

                                          =(6,-7) x (i, j)

                                          =6i-7j

Unit of motion vector

Motion Vector= (Distance moved by the object/Unit motion vector) × (Direction of motion vectors)

Workdone

Result:

   Work done to move an object

Step-by-step explanation:

The work done to move the object is:

The angle of the force with respect to change in the position vector is:

The magnitude of the work done is:

incomplete question. how do you expect anyone to you when you do not post the question in its entirety?