What are the intercepts of 7x+2y-14z=56 a. (8,0,0) (0,-28,0) (0,0,-4) b. (8,0,0) (0,28,0) (0,0,-4) c. (8,0,0) (0,28,0) (0,0,4) d. (8,0,0) (0,-28,0) (0,0,4)

Since the equation is in 3 variables, there will be 3 intercepts:

1) x-intercept
Where y and z coordinate are zero.
So, we can say
7x + 2(0)-14(0) = 56
So, x = 8 is the x-intercept

2) y-intercept
where x and z coordinate are zero
So, we can write
7(0) + 2y - 14(0) = 56
So, y = 28 is the y-intercept

3) z-intercept
where x and y coordinates are zero
So, we can write
7(0)+2(0)-14z=56
So, z=-4 is the z intercept

Therefore, the correct answer to this question is option B