Write the quadratic equation whose roots are 6 and -4 , and whose leading coefficient is 5. (use the letter x to represent the variable.)

The quadratic equation for this would be f(x) = 5x^2 - 10x - 120.

In order to find that, we need to start by taking our x intercept values and setting them equal to zero.

x = 6 > subtract 6 from both sides

x - 6 = 0

x = -4 > add 4 to both sides

x + 4 = 0

Now that we have both of these zero terms, we can multiply them to get a standard form.

f(x) = (x - 6)(x + 4)

And while this will give us the zeros we need, it will no give us the lead coefficient. So we must multiply by the desired lead coefficient.

f(x) = 5(x - 6)(x + 4)

f(x) = 5(x^2 - 6x + 4x - 24)

f(x) = 5(x^2 - 2x - 24)

f(x) = 5x^2 - 10x - 120

i think it is

step-by-step explanation:

a formal letter is a letter the you would send to a king

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^