Find the standard deviation, σ, for the binomial distribution which has the stated values of n and p. round your answer to the nearest hundredth. n = 1680; p = 0.57

σ ² = npq = np(1-p) = 1680*(0.57)*(1-0.57) = 411.768
=>
σ = sqrt(411.768) = 20.292 (to the nearest thousandth).

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.