The width of a rectangle is 40 centimeters. the perimeter is at most 520 centimeters. a. write and solve an inequality to find the length of the rectangle. b. write an inequality to find the area of the rectangle in square centimeters. a. 2(40) + 2ℓ ≤ 520; ℓ ≤ 220; a ≤ 40(220) b. 2(40) + 2ℓ ≥ 520; ℓ ≥ 220; a ≥ 40(220) c. 40 +ℓ ≥ 520; ℓ ≥ 480; a ≥ 40(480) d. 2(40) + 2ℓ ≤ 520; ℓ = 220; a = 40(220)