Use the grouping method to factor the polynomial below completely. x3 + 2x2 + 4x + 8 a. (x2 + 2)(x + 2) b. (x2 + 2)(x + 4) c. (x2 + 4)(x + 4) d. (x2 + 4)(x + 2)

So since there are 4 terms given, pair the first two and second 2.
(x^3 + 2x^2) + (4x + 8)   factor out the common terms in both brackets
x^2 (x + 2) + 4 (x + 2)   i factored out x^2 from bracket 1 and 4 from bracket 2
Notice that there are two terms left. x^2 (x + 2) and 4 (x + 2)
Also note that both these terms have matching brackets (x+2)
So you can "factor out" x+2 from both terms like this:
(x + 2) (x^2 + 4) < to get the second bracket, i just factored out x+2 and put the remaining x^2 and 4 into one bracket. So your answer is D.

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