2(x-3)^2+10=82 solve by isolating x

We have the following equation:
 2 (x-3) ^ 2 + 10 = 82
 We must clear x.
 We pass the constant terms to one side of the equation:
 2 (x-3) ^ 2 = 82 - 10
 2 (x-3) ^ 2 = 72
 (x-3) ^ 2 = 72/2
 (x-3) ^ 2 = 36
 Square root to both members:
 x-3 = +/- root (36)
 x-3 = +/- 6
 The solutions are:
 x1 = 6 + 3 = 9
 x2 = -6 + 3 = -3
 
 x1 = 9
 x2 = -3

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