Suppose a bag contains 4 white chips and 6 black chips what is the probability of randomly choosing a white chip not replacing it and then randomly choosing another white chip

Number of white chips = 4
Number of black chips = 6
Total number of chips = 4 + 6 = 10
Choosing the first white chip:
p(white chip) = 4/10 = 2/5

Now the numbers are:
Number of white chips = 3
Number of black chips = 6
Total number of chips = 3 + 6 =
Choosing the second white chip:
p(white chip) = 3/9 = 1/3

p(white chip followed by white chip) = 2/5 * 1/3 = 2/15

i believe your answer is b.

good luck!

cutie~