Which of the following statements are true about the equation below? x^2-6x+2=0 ( 1 ) the graph of the quadratic equation has a minimum value. ( 2 ) the extreme value is at the point (3,-7). ( 3 ) the extreme value is at the point (7,-3). ( 4 ) the solutions are x = -3 + or - the square root of 7 . ( 5 ) the solutions arex = 3 + or - the square root of 7. ( 6 ) the graph of the quadratic equation has a maximum value.

Option 1, 2, 5 are the correct answer.

Explanation:

 We have the quadratic equation,

 First derivative of the equation is given by 2x - 6 = 0

               So x = 3

At x = 3 the value of quadratic equation is extreme, corresponding y is given by , So extreme value is at (3,-7)

Second derivative of the quadratic equation is given by 2 ( positive value)

 Second derivative is positive so graph of equation has a minimum value.

Now root of the equation is given by

                                             or

Option 1, 2, 5 are the correct answer.              

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

it shoild be o

step-by-step explanation: