Which of the following statements are true about the equation below? x^2-6x+2=0 ( 1 ) the graph of the quadratic equation has a minimum value. ( 2 ) the extreme value is at the point (3,-7). ( 3 ) the extreme value is at the point (7,-3). ( 4 ) the solutions are x = -3 + or - the square root of 7 . ( 5 ) the solutions arex = 3 + or - the square root of 7. ( 6 ) the graph of the quadratic equation has a maximum value.

Option 1, 2, 5 are the correct answer.

Explanation:

 We have the quadratic equation,

 First derivative of the equation is given by 2x - 6 = 0

               So x = 3

At x = 3 the value of quadratic equation is extreme, corresponding y is given by , So extreme value is at (3,-7)

Second derivative of the quadratic equation is given by 2 ( positive value)

 Second derivative is positive so graph of equation has a minimum value.

Now root of the equation is given by

                                             or

Option 1, 2, 5 are the correct answer.              

6/20

step-by-step explanation:

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130