In rectangle date, the diagonals dt and ae intersect as s. if latex: ae=40 a e = 40 and latex: st=x+5 s t = x + 5 , find the value of x.

For this case we have the following diagonals:
 AE = 40
 ST = x + 5
 The intersection of the diagonals occurs when:
 AE = ST
 Therefore, matching we have:
 40 = x + 5
 Clearing x we have:
 x = 40-5
 x = 35
 
 The value of x is:
 x = 35