Find the zeroes of the function algebraically. write the answer, if applicable, in fraction form. ƒ(x) = 2x2 - 3x - 20

First let's factorise the function:
f(x) = 2x^2 - 3x - 20
= (2x + 5)(x - 4)

Now make f(x) = 0:
0 = (2x + 5)(x - 4)
x = -5/2 or x = 4

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Ithink it's b sorry if i'm wrong