Simon has 160 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width www (in meters) is modeled by a(w)=-w(w-80) what is the maximum area possible?

It is given in the question , that Simon has 160 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width w (in meters) is modeled by

Which represents parabola and the parabola is maximum at its vertex, that is

Therefore the width is 40 meters and the area is

Simon has 160 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width www (in meters) is modeled by a(w)=-w(w-80) what is the maximum area possible?

Solution:

Let width of the rectangular garden=w

Perimeter of the rectangular garden=2(length+width)

160=2(length+w)

Divide by 2 on both sides

80=length+w

So, Length= 80-w

So, Area of rectangular garden= Length* Width

Area, A(w)=(80-w)(w)

Area, A(w)=-w²+ 80 w

Area is a quadratic equation. And, quadratic equation makes a parabola.

For the maximum area, We need to find the vertex of the parabola.

The formula for x-coordinate of the vertex=

x-coordinate of vertex=

x-coordinate of vertex=40

So, Width= 40 meters

Length=80-w=80-40=40 meters

Maximum area possible=Length* Width=40*40=1600 square meters

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.

it is true

step-by-step explanation:

all the combinations add up i used   calculator