What two numbers can be multiplied to be 60 and added to be -16

Let us assume the two numbers to be "x" and "y".
Then
xy = 60
x = 60/y
And
x + y = -16
Putting the value of "x" from the first equation in the second equation we get
x + y = - 16
(60/y) + y = - 16
y2 + 60 = - 16y
y^2 + 16y + 60 = 0
y2 + 10y + 6y + 60 = 0
y(y + 10) + 6(y + 10) = 0
(y + 10) ( y + 6) = 0
Then
y + 10 = 0
y = -10
So
x = 60/y
   = - (60/10)
   = -6
When
y + 6 = 0
y = - 6
Then
x = 60/y
   = - (60/6)
   = - 10
So the two unknown numbers are - 6 and - 10.

Definitely

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answer:
congruent segments
step-by-step explanation:
congruent segments. take a line, cut it in half, superipose one half over the other half; you'll have congruence.