Across country coach records the number of miles his athletes on the junior varsity and varsity teams ran today and displays the data in the provided dot plots. given the shape of each distribution, determine which measures of center and spread are appropriate for him to use to summarize the data from each team.

For the first dot plot, the best measure of center to use would be the mean because the data is symetric. If you evened these all out, the mean would be a good measurement because both sides are evenly distributed.  The best measure of variation would be the Mean absolute deviation because you will use the mean to calculate it.

For the second dot plot, the best measure of center would be the median because the data is skewed left.  This means that it is not evenly distributed on both sides for choosing the actual middle number would represent it best.  The interquartile range (the distance from the beginning to the end of the middle half of the data) is the best measure of variation, because it will not account for the data that is skewed.

Hi! mark me brainliest if i : )y = 0.213x – 352.0    represents this linear model shown in the data table.plug in the values of x into the equation for a double check.let's try 1980.y = 0.213(1980) – 352.0y = 69.74which is closest to the 70.1 whereas other options do not satisfy the condition.