There are 36 chocolates in a box, all identically shaped. there 10 are filled with nuts, 12 with caramel, and 14 are solid chocolate. you randomly select one piece, eat it, and then select a second piece. find the probability of selecting a solid chocolate candy followed by a nut candy.

Step-by-step explanation:

Given : The total number of chocolates in the box = 36

The number of chocolates filled with solid chocolate  =14

The number of chocolates filled with nuts = 10

Now, the probability of selecting a solid chocolate candy is given by :-

Now the chocolates left in box = 36-1=35

The probability of selecting next chocolate a nut candy will be :-

Now, the probability of selecting a solid chocolate candy followed by a nut candy will be:_

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.