11) jeff and jason are diving near a corral reef in the ocean. jason is swimming along the bottom of the ocean floor 188.82 feet from the boat's anchor which lies directly below the boat at a depth of 172.22 feet. if jeff is 20 feet directly above jason, how far is jeff from the boat? (round to nearest tenth)

jeff is 255.5 ft away from the boat.

Step-by-step explanation:

The data is:

Jason is 188.82 feet away from the boat's anchor.

The anchor is 172.22 feet under the boat.

Jeff is 20 feet above Jason.

this means that Jason is 172.22 feet under the surface of the water (because the anchor must be attached to the bottom of the ocean floor) and Jeff is right 20 feet above Jason, so Jason is 152.22 ft under the surface

Now, from this, we can know that the distance from Jason to the boat is equal to the hypotenuse of the rectangle triangle that can be formed with the distance between Jeff and the anchor (that is the same as the distance between Jason and the anchor), and the distance between the Jeff and the surface of the water.

D = √((188.82 ft)^2 + (152.22ft)^2) = 255.5 ft

14.29%

step-by-step explanation:

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of