John needs to paint one wall in his school. he knows that 1 can of paint covers an area of 24 square feet. john uses a meter stick to measure the dimensions of the wall as shown. [1 meter = approximately 39 inches] what is the fewest number of cans of paint john can use to paint the wall?

The complete question in the attached figure

step 1
find the area of the wall

[area of the wall]=[area of rectangle]+[area of triangle]
[area of the wall]=[3*2]+[3*1/2]----> 7.5 m²

1 m²-------> 10.7639 ft²

area of the wall------> 7.5*10.7639------> 80.73 ft²

we know that
1 can of paint covers an area of --------> 24 ft²
x---------------------------------------------> 80.73 ft²
x=80.73/24---------> x=3.36 can of paints

the answer is
The fewest number of cans is 4

I’m not absolutely sure but i think it’s 7x6x5x4x3x2=5040 because as the first character you can take any of the 7 given then you are left with 5 then 6 then 4 etc.