The function latex: l=.8t^2 l = .8 t 2 models the relationship between l, the length in feet of a pendulum, and t, the period in seconds of the pendulum. which value is closest to the period in seconds for a pendulum that is 30 feet long?

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome