The sum of four consecutive integers 130 what is the third number in the sequence

If x is the first number in the sequence, you can represent the next consecutive number using (x+1), the one after with (x+2), etc.  We can set up an equation like this:

x + (x+1) + (x+2) + (x+3) = 130

This can be simplified to:

4x + 6 = 130

Now subtract 6 from each side:

4x = 124

Next we divide each side by 4:

x = 31

We have the first number in the sequence, but we need the THIRD number.  Since we've already established that (x+2) would be the third number, we can just plug in x.

31 + 2 = 33

The third number in this sequence is 33.