2. a basket contains 6 apples, 5 bananas, 4 oranges and 5 peaches. if you randomly choose one piece of fruit, eat it and then choose another, what is the probability that you would choose a banana and then an apple? (enter your answer as a whole number percent.)

8% as a whole number percent

Step-by-step explanation:

Number of;

Apples = 6

Bananas = 5

Oranges = 4

Peaches = 5

Total number of fruits in the basket = 6 + 5 + 4 + 5

= 20

Probability of picking a banana and then an apple

= (5/20) × (6/19)

= 30/380

= 3/38

=7.89% ≈ 8%

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

do your own work and don"t cheat.

step-by-step explanation: