Christine is currently taking a college astronomy class and the instructor often gives quizzes. on the past seven quizzes, christine got the scores shown below. find the standard deviation, rounding to one more decimal place than is present in the original data. 50 15 31 27 11 42 71

The answer is 20.9 when rounded it is 21

19.4

Step-by-step explanation:

Given data,

50,    15,       31,        27,         11,        42,        71,

Let x represents the score,

Here, the number of scores, n = 7,

Thus, the mean score is,

Hence, the standard deviation of the given data is,

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west