Abox without a top is made from a rectangular piece of cardboard, with dimensions 4 m by 2 m, by cutting out square corners with side length x. which expression can be used to determine the greatest possible volume of the cardboard box? (x−4)(x−2)x (x−4)(x−2)x (4−2x)(2−2x)x (4x−2)(2x−4)

The expression that can be used to find the volume of the cardboard box is:

(4−2x)(2−2x)x

Step-by-step explanation:

A box without a top is made from a rectangular piece of cardboard, with dimensions 4 m by 2 m, by cutting out square corners with side length x.

i.e. the box is in the shape of a cuboid.

Now the volume of a box is same as the volume of a cuboid.

We know that the volume of a cuboid is given as:

Volume of cuboid=Length×Breadth×Height.

So, the length of the cuboid box is: 4-2x

and the width of the box is: 2-2x

Also, the height of box is: x

Hence, the volume of cuboid is:

Hence, the expression for the volume of cuboid box is:

             (4−2x)(2−2x)x

(4−2x)(2−2x)x

Step-by-step explanation: Just confirming the answer :)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

.19875994384

step-by-step explanation:

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