Atriangular prism and two nets are shown:

a right triangular prism is shown with two nets. the triangular base of the prism has height 5 inches, base 12 inches, and hypotenuse 13 inches. the length of the prism is 14 inches. net a has 3 rectangles having dimensions 5 by 14, 14 by 12, and 14 by 13, and two triangles having legs 5 inches and 12 inches. net b has 3 rectangles having dimensions 5 by 13, 13 by 12, and 13 by 14, and two triangles having legs 5 inches and 12 inches.

which is the correct net of the prism and what is the surface area of the prism?
pick from the three answers below

net a with 420 square inches

net a with 480 square inches

net b with 510 square inches

net b with 534 square inches

Option B. Net A with 480 square inches.

Step-by-step explanation:

The net for triangular prism consists of

2 identical triangles, here all nets have sides 5", 12", and 13".

3 rectangles, all with a common dimension: the Length or height

H=14 inches of the prism.

Each of the 3 rectangles should have dimensions

H=14 plus one of the following:

each of 5, 12, 13 corresponding to one side of the base (triangle).

So the dimensions of the rectangles are

5 × 14, 12 × 14, 13 × 14

And dimensions of the triangles are

5,12 and 13.

The total surface area is therefore

(5+12+13)×14 + 2×(5×12/2)

(30)(14)+2(60/2)

= 420+2(60/2)

= 420+2(30)

= 420+60

= 480 square inches.

Net A with 480 square inches is the correct net of the prism.

The answer is B Net B with 480 square inches. I took the test and got it right. Have a great dday.

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